On a certain day, three computer technicians took turns in manning a 24-hour internet shop. The number of hours Cesar, Bert, and Danny were on duty was in the ratio 3:4:5. The shop owner pays them P50 per hour. How much would Danny receive for that day?

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Multiple Choice

On a certain day, three computer technicians took turns in manning a 24-hour internet shop. The number of hours Cesar, Bert, and Danny were on duty was in the ratio 3:4:5. The shop owner pays them P50 per hour. How much would Danny receive for that day?

Explanation:
When quantities are shared in a ratio, you allocate the total according to the number of parts each person gets. Here the shop is open 24 hours and the three technicians’ hours are in the ratio 3:4:5. The total number of parts is 3 + 4 + 5 = 12, so each part equals 24 ÷ 12 = 2 hours. Danny’s share is 5 parts, which is 5 × 2 = 10 hours. At P50 per hour, Danny earns 10 × 50 = P500. The other numbers don’t fit because they don’t correspond to 10 hours at the given rate, whereas the distribution dictates 10 hours for Danny, yielding P500.

When quantities are shared in a ratio, you allocate the total according to the number of parts each person gets. Here the shop is open 24 hours and the three technicians’ hours are in the ratio 3:4:5. The total number of parts is 3 + 4 + 5 = 12, so each part equals 24 ÷ 12 = 2 hours. Danny’s share is 5 parts, which is 5 × 2 = 10 hours. At P50 per hour, Danny earns 10 × 50 = P500. The other numbers don’t fit because they don’t correspond to 10 hours at the given rate, whereas the distribution dictates 10 hours for Danny, yielding P500.

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